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Proof of $\text{Avg}(X)$ does not change the probability

Lets look at two samples $S$ and $S^*$, if you are presented with a sample
$S$ you know that it has average $x$ and a sample $S^*$ you know that it has average $x^*$.
Why the following does not hold true, $P(S^*)=P(S)$.

A:

Because if $S^*=S$ then the average is $x^*=x$.
If $S^*
eq S$ then the averages are not the same, because the average of $S^*$ is the average of those elements of $S^*$ which are also in $S$, and this is not the same as the average of $S$.
For instance, suppose the average of $S$ is $1.5$ and the
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